The point [math](x_0, y_0)[/math] lies in the first quadrant. Each line through [math](x_0, y_0)[/math] with negative slope determines a triangle in the first quadrant. Among all such triangles, find the one with minimum area.
Drag point B to change the slope of the line. Drag point A to change the [math](x_0, y_0)[/math] .
