New formular in a triangle
Let $ABC$ be a triangle, the perpendicular bisector of $BC$
meets the circle at $D$, $E$ (see Figure). Then
$|AB-AC|=2AD.\sin{\frac{\angle CAB}{2}}$
$|AB+AC|=2AE.\cos{\frac{\angle CAB}{2}}$
- Target Group (Age)
- 3 – 19+
- Language
- English
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