For the equation 8^x=1/64 we have that [color=#0a971e]x[/color]=log[color=#c51414]8[/color](1/64)=log[color=#c51414]8[/color](1)-2*log[color=#c51414]8[/color](8)=0-2*(1)=[color=#0a971e]-2[/color]
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