Riemann Zeta Circles, and parabola. For no reason at all.

Obtained these eq's by simplifying the expression for the riemann sum, with a(x) coming from treating the real part as 0 when x is 1/2. Parabolas are summations, and they sum to around -1/12 as you let "n" increase. The circles are just the size of your chosen value for "n", this would be equation b(x). Note that things may be slow to load, this site hates my equations.

 

KwolZ

 
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