Parameterize the line containing the two points [math]\left(1,-1,3\right)[/math] and [math]\left(-2,1,0\right)[/math].
There is not a unique correct answer to this question of course, as any curve could potentially be the image curve of infinitely many paths. However the standard way to parameterize a line given two points is to find the slope vector:[br][math]\left(\Delta x,\Delta y,\Delta z\right)=\left(-2-1,1-\left(-1\right),0-3\right)=\left(-3,2,-3\right)[/math][br]and then build the parameterization as follows:[br][br][math]\vec{c}\left(t\right)=\left(1,-1,3\right)+t\left(-3,2,-3\right)=\left(1-3t,-1+2t,3-3t\right),t\in\mathbb{R}[/math][br][br]Some notes:[br][list][*]If we change the domain of definition to [math]\left[0,1\right][/math] this approach will parameterized the directed line segment from the first point to the second.[/*][*]The speed of this parameterization will always be the length of the slope vector. To create a unit-speed parameterization you can just replace [math]t[/math] with [math]\frac{t}{\left|\left|\left(\Delta x,\Delta y,\Delta z\right)\right|\right|}[/math].[/*][/list]